Chemistry, asked by dianellorencatbagan, 5 months ago

Naturally occuring boron consists
of 80.22% 11B (nuclidic mars = 11-009) and 19.78%
11.009 of another
isotope. To account for the atomic mass 10.810 , what must be the nuclidic mass of
the other isotope?

Answers

Answered by itzMissMod

Answer:

Calculate the percentage of each isotope in natural boron. ... atomic mass = 100Atomic weight of first isotope×x+atomic weight of second ... · या पानाचे भाषांतर करा

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Naturally occuring boron consistsof 80.22% 11B (nuclidic mars = 11-009) and 19.78%11.009 of anotherisotope. To account for the atomic mass 10.810 , what must be the nuclidic mass ofthe other isotope?​

Answers

Naturally occuring boron consists
of 80.22% 11B (nuclidic mars = 11-009) and 19.78%
11.009 of another
isotope. To account for the atomic mass 10.810 , what must be the nuclidic mass of
the other isotope?