Question

Nature of quadratic equation 3x2-6x+2=0

Answer 1

Step-by-step explanation:

3 x^{2} -2√6x+2=0

3 x^{2} -√6x-√6x+2=0

√3 x^{2} *√3 x^{2} -√3x*√2x-√3x*√2x+√2*√2=0

√3x(√3x-√2)-√2(√3x-√2)=0

(√3x-√2)(√3x-√2)=0

x=√2/√3

Therefore the equation has two equal roots; √2/√3

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Answer 2

Answer:

60

Step-by-step explanation:

First, we need to rewrite the equation in standard quadratic form:

$3x^{2} +6x-2=2-2$

$3x^{2} +6-2=0$

For  $ax^{2} +bx+c=0$ , the values of  x  which are the solutions to the equation given

The discriminate is the portion of the quadratic equation within the radical:  

$b^{2} -4ac$

If the discriminate is:

- Positive, you will get two real solutions

- Zero you get just ONE solution

- Negative you get complex solutions

To find the discriminant for this problem substitute:

3  for  a

6  for  b

-2 for c

$6^{2} -(4*3*-2)$⇒

$36-(-24)$⇒

$36+24$⇒

$60$

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