Question

Nature of root for 2x2-6x+3=0​

Answer 1

Answer:

d>0. roots are real and distinct.

Step-by-step explanation:

a=2, b=-6, c=3

discriminant d=b^2-4ac=(-6)^2-4×2×3

=36-24=12>0

d>0. roots are real and distinct.

Answer 2

Answer:

Real and unequal

Step-by-step explanation:

comparing the given equation with

ax^2+ bx + C=0

here a=2 b=-6 c=3

value of b^2-4ac= -6^2 - 4 ×2×3

= 36 - 24

= 12

b^2-4ac = 12 that is greater than 0

therefore roots are real and unequal.