Question

nature of roots for
${x }^{2} - 4x + 3 = 0$
​

Answer 1

Hey friend,

Here is the solution :-

$here \: a = 1 \: \: \: \: b = - 4 \: \: \: \: \: c = 3 \\ \\ as \: we \: know \: that \: d = {b}^{2} - 4ac \: (discriminate) \\ \\ d = ({ - 4})^{2} - 4(1)(3) \\ \\ d = 16 - 12 \\ \\ d = 4 \\ \\ since \: the \: root \: is \: positive \: so \: the \\ nature \: of \: the \: root \: is \\ real \: and \: distinct.$

I hope this will help you....

Answer 2

Answer:

$(x - 3) \\(x - 1)$