Question

nature of roots of quadratic equation root 2 x square minus 3 upon root 2 X + 1 by root 2 is equal to zero ​

Answer 1

Answer:

$\sqrt{2}$x² - $\frac{3}{\sqrt{2} }$x + $\frac{1}{\sqrt{2} }$ = 0

for nature of roots we apply x =  $\frac{-b+-\sqrt{b^{2} -4ac} }{2a}$

we get x = 1&1/2

so roots are real and distinct

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Answer 2

This is step by step explanation for you.

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