Question

nature of Roots of quadratic equation x2-8x+16=0​

Answer 1

Step-by-step explanation:

x2-8x+16=0

a=1,b=-8,c=16

b2-4ac=(-8)2-4×1×16

=64-64

=0

b2-4ac=0

This quadratic equation is real and equal

Answer 2

Answer:

formula : Δ=b²-4ac

a=1

b=-8

c=16

(-8)²-4(1)(16)

64-64

=0=0

the nature of roots of quadratic equation is equal roots

hope it useful for u