Nature of roots of the equation X2+2X+4=0 is
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Answer:
the root of eqn is unreal
hi mate,
X^2+2X+4=0
Solving x^2+2x+4 = 0
by the Quadratic Formula .
- B ± √ B^2-4AC
x = ————————
2A
In our case, A = 1
B = 2
C = 4
Accordingly, B^2 - 4AC =
4 - 16 =
-12
Applying the quadratic formula :
-2 ± √ -12
x = ——————
2
Both i and -i are the square roots of minus 1
Accordingly,√ -12 =
√ 12 • (-1) =
√ 12 • √ -1 =
± √ 12 • i√ 12 = √ 2•2•3 =
± 2 • √ 3
√ 3 , rounded to 4 decimal digits, is 1.7321
So now we are looking at:
x = ( -2 ± 2 • 1.732 i ) / 2
Two imaginary solutions :
x =(-2+√-12)/2=-1+i√ 3 = -1.0000+1.7321i
or:
x =(-2-√-12)/2=-1-i√ 3 = -1.0000-1.7321i
Two solutions were found :
x =(-2-√-12)/2=-1-i√ 3 = -1.0000-1.7321i
x =(-2+√-12)/2=-1+i√ 3 = -1.0000+1.7321i
i hope it helps you.