Question

nature of roots of the quadratic equation X square + 2 X + 3 equal to zero​

Answer 1

Answer:

Step-by-step explanation:

x^2 +2x + 3

a = 1 , b = 2 , c= 3

D= b^2-4ac

D= (2)^2 - 4(1)(3)

D= 4-12

D = -8

:. Roots does not exist... D < 0.

Answer 2

Step-by-step explanation:

let a= 1

b=2

c=3

then a,b,c are real then,

delta =0 then roots are real and equal

delta >0then roots are real and district

delta <0 then roots are conjugate complex number

a,b,c are rational then,

delta=0 then roots are rational and equal

delta >0 then roots are conjugate suards

delta <0 then roots are complex numbers

delta =0

; delta =b^2- 4ac

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