Question

Nature of The roots of quadratic equation 9x2 - 6x +1 =0 are ??

Answer 1

HEY DEAR______❤❤❤❤❤❤
HERE IS YOUR ANSWER:-)
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=>9x^2 - 6x + 1

=>a = 9,b = -6,c = 1

=> a × c = 9 × 1 = 9

=> 9x^2 - ( 3 + 3)x + 1

=> 9x^2 - 3x - 3x + 1

=> (9x^2 - 3x) (-3x +1)

=> 3x(3x - 1) -1(3x - 1)

=> (3x - 1) (3x - 1)

Roots of the equation
=> 3x - 1 = 0 and 3x - 1 = 0
=> 3x = 1 and 3x = 1
=> x = 1/3 and x = 1/3

Hope it helps you
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@AKJORDAN

Answer 2

Answer:

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