Question

Nature of the roots of the equation 2 x^2- 3 x + 5 = 0

Answer 1

Answer:

by discriminate formula

D=b^2-4ac

here in equation ,

a=2 , b=-3 , c=5

so putting the value of a,b,c in formula

D=(-3)^2-4*2*5

D=9-40

D=-31

here -31 <0

so this equation has no real roots

Answer 2

Step-by-step explanation:

comparing this equation with

ax²+bx+c=0

then we get

a= 2 ,b=2, c= -3

b²-4ac

=2²-4×2×(-3)

=4-4(-6)

=4-24

=-20

b²-4ac> -20

so roots are real and unequal

hope you help this