Question

Nature of the roots of the quadratic equation : 2x ² - 6x + 3 = 0 is ​

Answer 1

Step-by-step explanation:

We could find the nature of roots by finding Discriminant

By using the Formula

b^2-4ac

(-6)^2-4×2×3

36-24

12>0

Therefore 12>0 then the given quadratic eq. have distinct real roots

Sorry but ur question was incomplete(2x^2-6x(+-)3??? I gave the +value