Hindi, asked by mahikag4, 3 months ago

नवरह भवुंगम ति बसै, मुंत् ि िागै करई meaning?

Answers

Answered by MRsteveAustiN
0

</p><p>\documentclass[12pt]{article}</p><p>\usepackage{tikz}</p><p>\newcommand\FillSquare[5]{%</p><p>\fill[#2] (0,0) rectangle +(0.5*#1,0.5*#1);</p><p>\fill[#3] (0.5*#1,0cm) rectangle +(0.5*#1,0.5*#1);</p><p>\fill[#4] (0,0.5*#1) rectangle +(0.5*#1,0.5*#1);</p><p>\fill[#5] (0.5*#1,0.5*#1) rectangle +(0.5*#1,0.5*#1);</p><p>}</p><p></p><p>\newcommand\MySquare[5]{%</p><p>\FillSquare{#1}{#2}{#3}{#4}{#5}</p><p>\draw (0,0) rectangle (#1,#1);</p><p>\draw (0,0.5*#1) -- +(#1,0);</p><p>\draw (0.5*#1,0) -- +(0,#1);</p><p>}</p><p></p><p>\newcommand\MyCircle[5]{%</p><p>\fill[#4] (0,0) arc[radius=0.5*#1,start angle=180,end angle=90] -- +(0,-0.5*#1) --cycle;</p><p>\fill[#5] (#1,0) arc[radius=0.5*#1,start angle=0,end angle=90] -- +(0,-0.5*#1) --cycle;</p><p>\fill[#3] (#1,0) arc[radius=0.5*#1,start angle=0,end angle=-90] -- +(0,0.5*#1) -- cycle;</p><p>\fill[#2] (0.5*#1,-0.5*#1) arc[radius=0.5*#1,start angle=-90,end angle=-180] -- +(0.5*#1,0) -- cycle;</p><p>\draw (0.5*#1,0) circle [radius=0.5*#1];</p><p></p><p>\draw (0,0) -- +(#1,0);</p><p>\draw (0.5*#1,-0.5*#1) -- +(0,#1);</p><p>}</p><p></p><p>\newcommand\MyShape[9]{%</p><p>\fill[#2] (0,0) arc[radius=0.5*#1,start angle=270,end angle=180] -- +(0.5*#1,0) --cycle;</p><p>\fill[#5] (-0.5*#1,0.5*#1) arc[radius=0.5*#1,start angle=180,end angle=90] -- +(0,-0.5*#1) --cycle;</p><p>\fill[#6] (1.5*#1,0.5*#1) arc[radius=0.5*#1,start angle=0,end angle=90] -- +(0,-0.5*#1) --cycle;</p><p>\fill[#9] (1.5*#1,0.5*#1) arc[radius=0.5*#1,start angle=0,end angle=-90] -- +(0,0.5*#1) -- cycle;</p><p>\FillSquare{#1}{#3}{#4}{#7}{#8}</p><p>\draw (#1,0) -- +(-#1,0) </p><p>  arc[radius=0.5*#1,start angle=270,end angle=90] -- +(#1,0)</p><p>  arc[radius=0.5*#1,start angle=90,end angle=-90] -- cycle;</p><p>\draw (-0.5*#1,0.5*#1) -- +(2*#1,0);</p><p>\draw (#1,0) -- +(0,#1);</p><p>\draw (0.5*#1,0) -- +(0,#1);</p><p>\draw (0,0) -- +(0,#1);</p><p>}</p><p></p><p></p><p></p><p></p><p></p><p>

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