Question

Navjot ate 3/9 of a cake whereas Rajvinder ate 1/2 of the cake. compare​

Answer 1

➤ Answer :-

Cake ate by Navjot $= \sf\frac{3}{9}$

Cake ate by Rajvinder $= \sf\frac{1}{2}$

$\dashrightarrow \sf \frac{3}{9} \: \boxed{?} \: \frac{1}{2}$

LCM of 9 and 2 is 18.

$\dashrightarrow \sf \frac{3 \times 2}{9 \times 2} \: \boxed{{?}} \: \frac{1 \times 9}{2 \times 9}$

$\dashrightarrow \sf \frac{6}{18} \: \boxed{ < } \: \frac{9}{18}$

$\Huge\therefore$Rajvinder ate more cake than Navjot.

Answer 2

Answer:

$\huge {\blue {\bf {question}}}$

Navjot ate 3/9 of a cake whereas Rajvinder ate 1/2 of the cake. compare each

$\huge {\green {\bf {answer}}}$

[We have to find the LCM of both denominator to compare]

$LCM \: of \: 2 \: and \: 9 = 18$

$\frac{3}{9} = \frac{3 \times 2}{9 \times 2} = \frac{6}{18}$

$\frac{1}{2} = \frac{1 \times 9}{2 \times 9} = \frac{9}{18}$

Therefore , Rajvinder eat more cake than Navjot