Math, asked by Akash8341, 1 year ago

Navya buys a certain number of toys at 12per rs 9 and the same number at 18 per rs9. If she sells them at 18 per rs15 does shegain or lose and by what percentage?

Answers

Answered by TooFree
8

Answer:

A profit of 20.83%

Step-by-step explanation:

Define x:

Let the number of toys bought at 12 per Rs 9 be x

The number of toys bought at 18 per Rs 9 is also x

Find the total purchase:

12 toys = Rs 9

1 toy = 9 ÷ 2 = Rs 3/4

x toys = Rs (3/4)x

18 toys = Rs 9

1 toy = 9 ÷ 18 = Rs 1/2

x toys = Rs (1/2)x

Total toys = x + x = 2x

Total cost = (3/4)x + (1/2)x = Rs (5/4) x

Find the cost of 1 toy:

2x toys = Rs 5/4 x

1 toy = (5/4)x ÷ 2x

1 toy = Rs 5/8

Find the selling price of 1 toy:

18 toys = Rs 15

1 toy = 15 ÷ 18 = Rs 5/6

Find the profit/loss:

Since 5/6 is greater than 5/8

=> It is a profit

Profit = 5/6 - 5/8 = Rs 5/24

Find the profit percentage:

Profit percentage = 5/24 x 100 = 20.83%

Answer: A profit of 20.83%

Answered by captainkhan85
7

She bought 12 toys at Rs 9.

And 18 toys at Rs 9

Then 12toys = 18 9

12 ?==6

Total 24toys =(9+6)15.

She sells 18 toys at Rs 15.

Now 18 15

(12+12) 24 ? ==>20

Profit %ge is 15/20*100=300/4=33 1/3%.

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