Question

Nazima is fly fishing in a stream. The tip of her fishing rod is 1.8 m about the surface of the water and the fly at the end of the string rests on the water 3.6 m away and 2.4 m from a point directly under the tip of the rod. Assuming that her string ( from the tip of her rod to the fly ) is taut, how much string does she have out ( see given figure)? If she pulls the string at the rate of 5 cm per second, what will the horizontal distance of the fly from her after 12 second?

Answer 1

Answer:

3m of string is out.  the fly will be 240 cm or 2.4 m away from her after 12 seconds

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Answer 2

Answer:

Ans. I. To find The length of AC.

By Pythagoras theorem,

AC2 = (2.4)2 + (1.8)2

AC2 = 5.76 + 3.24 = 9.00

AC = 3 m

Length of string she has out= 3 m

Length of the string pulled at the rate of 5 cm/sec in 12 seconds

= (5 x 12) cm = 60 cm = 0.60 m

Remaining string left out = 3 – 0.6 = 2.4 m

II. To find: The length of PB

PB2 = PC2 – BC2

= (2.4)2 – (1.8)2

= 5.76 – 3.24 = 2.52

PB = = 1.59 (approx.)

Hence, the horizontal distance of the fly from Nazima after 12 seconds

= 1.59 + 1.2 = 2.79 m (approx.)