nC5 = nC8 and. 15Cn = 15Cm Then find the possible values of m
Answers
Answered by
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Step-by-step explanation:
n
C
7
=
n
C
5
7!×(n−7)!
n!
=
5!×(n−5)!
n!
7×6
1
=
(n−5)(n−6)
1
comparing LHS and RHS we get, n=12
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