NCERT BRAINLIEST QUESTION
How can three resistors of resistance 2 ohms , 3 ohms and 6 ohms be connected to give a total resistance of (a) 4 ohms and (b) one ohms?
Answers
2ohm and 3 ohm should be connected in parallel and 6ohm. in parallel.
1/ R = 1/2+1/3+1/6
= 3+2+1/6 = 6/6 = 1ohm
Now , to obtain 4ohm. resistance we need to connect 3ohm and 6ohm is parallel and 2ohm in series.
1 / R = 1 /3 + 1/6 = 3 / 6
R = 6/3 = 2
Total resistance=2+2 = 4ohm.
Then the net R from parallel connection is connected in series with the remaining 2 Q resistor to get a total resistance of 4 Q. This is because in series combination:
R=R1+ R2
R=2 + 2
R=4Ω
The arrangement of three resistors of 2,3Ω and 6Ω which gives a total resistance of 4Ω can now be represented as follows:
Thus, we can obtain a total resistance of 4Ω by connecting parallel combination of 3Ω and 6Ω resistors in series with 2Ω resistor.
(b) In order to obtain a total resistance of 1Ω from three resistors of 2Ω, 3Ω and 6Q, all the three resistors should be connected in parallel. This is because in parallel combination:
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