Ncert class 7 maths try these solutions of page no. 170 Q1 to Q4
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Step-by-step explanation:
Given Ncert class 7 maths try these solutions of page no. 170 Q1 to Q4
- The question is
- 1. Rs 10,000 is invested at 5% p.a. Find the interest at the end of one year.
- So for Rs 100, interest is Rs 5
- So for Re 1 interest will be 5/100
- So for Rs 10,000 interest will be 10,000 x 5 / 100
- 100 x 5
- = Rs 500
- 2. Rs 3,500 is given at 7% p.a rate of interest. Find the interest which will be received at the end of two years.
- So for Rs 100 interest for one year is Rs 7
- So for Re 1, interest is 7/100
- Now for Rs 3,500 interest will be 7/100 x 3500
- = 35 x 7
- = Rs 245
- So interest for 1 year it is Rs 245
- Therefore interest for 2 years it will be 245 x 2
- = Rs 490
- 3. Rs 6050 is borrowed at 6.5% rate of interest p.a. Find the interest and the amount to be paid at the end of 3 years.
- So for Rs 100 interest for one year is Rs 6.50
- For Re 1 interest will be 6.50 / 100
- Therefore for Rs 6050 interest will be 6.50 /100 x 6050
- = Rs 393.25
- So interest for 1 year is Rs 393.25
- Therefore interest for 3 years will be 393.25 x 3
- = Rs 1179.75
- Now total amount to be paid will be 6050 + 1179.75
- = Rs 7229.75
- 4. Rs 7000 is borrowed at 3.5% rate of interest p.a borrowed for 2 years. Find the amount to be paid at the end of second year.
- So for Rs 100 interest for one year will be Rs 3.5
- So for Re 1, interest will be 3.5 / 100
- Therefore for Rs 7000 interest will be 3.5 / 100 x 7000
- = Rs 245
- So interest for 1 year is Rs 245
- Therefore interest for 2 years will be 245 x 2
- = Rs 490
- Now total amount to be paid at the end of second year will be 7000 + 490
- = Rs 7490
Reference link will be
https://brainly.in/question/4929849
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Answer:
p=10,000
R=5 percentage
T=1year
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