Math, asked by sankalpyadav3388, 9 months ago

Ncert class 7 maths try these solutions of page no. 170 Q1 to Q4

Answers

Answered by knjroopa

Step-by-step explanation:

Given Ncert class 7 maths try these solutions of page no. 170 Q1 to Q4

The question is
1. Rs 10,000 is invested at 5% p.a. Find the interest at the end of one year.
So for Rs 100, interest is Rs 5
So for Re 1 interest will be 5/100
So for Rs 10,000 interest will be 10,000 x 5 / 100
100 x 5
= Rs 500
2. Rs 3,500 is given at 7% p.a rate of interest. Find the interest which will be received at the end of two years.
So for Rs 100 interest for one year is Rs 7
So for Re 1, interest is 7/100
Now for Rs 3,500 interest will be 7/100 x 3500
= 35 x 7
= Rs 245
So interest for 1 year it is Rs 245
Therefore interest for 2 years it will be 245 x 2
= Rs 490
3. Rs 6050 is borrowed at 6.5% rate of interest p.a. Find the interest and the amount to be paid at the end of 3 years.
So for Rs 100 interest for one year is Rs 6.50
For Re 1 interest will be 6.50 / 100
Therefore for Rs 6050 interest will be 6.50 /100 x 6050
= Rs 393.25
So interest for 1 year is Rs 393.25
Therefore interest for 3 years will be 393.25 x 3
= Rs 1179.75
Now total amount to be paid will be 6050 + 1179.75
= Rs 7229.75
4. Rs 7000 is borrowed at 3.5% rate of interest p.a borrowed for 2 years. Find the amount to be paid at the end of second year.
So for Rs 100 interest for one year will be Rs 3.5
So for Re 1, interest will be 3.5 / 100
Therefore for Rs 7000 interest will be 3.5 / 100 x 7000
= Rs 245
So interest for 1 year is Rs 245
Therefore interest for 2 years will be 245 x 2
= Rs 490
Now total amount to be paid at the end of second year will be 7000 + 490
= Rs 7490

Reference link will be

https://brainly.in/question/4929849

Answered by bhadranivansh2

Answer:

p=10,000

R=5 percentage

T=1year

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