NCERT CLASS IX - Science Textbook
Chapter 12 - Sound
An echo returned in 3 s. What is the distance of the reflecting surface from the source, given that the speed of sound is 342 m s - '1?
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Answered by
1
we know that,in the case of echo, 2d =v*t
[ where d=distance between reflecting surface and source, v=velocity,
t= tot.time taken ]
here,t = 3s
v = 342 m/s
hence 2d = 342*3 = 1026 m
thus, d = 1026/2= 513 m
[ where d=distance between reflecting surface and source, v=velocity,
t= tot.time taken ]
here,t = 3s
v = 342 m/s
hence 2d = 342*3 = 1026 m
thus, d = 1026/2= 513 m
Answered by
0
time = 3 second
v = 342 m /s
s=v×t
s=342×3
s=1026
we have to find the distance so total distance cover =
s+s = 1026
2s=1026
s=513 m
v = 342 m /s
s=v×t
s=342×3
s=1026
we have to find the distance so total distance cover =
s+s = 1026
2s=1026
s=513 m
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