Question

ncert grade 9 an object of mass 39 kg produces an accelaration of 10 m/s ² by the application of cirtum amount of force find the force ​

Answer 1

AnswEr :

• Mass = 39 kg
• Acceleration = 10 m/s²

By second law of motion, we know that :

➝ F = ma

➝ F = 39 * 10

➝ F = 390 N

Answer 2

GIVEN :-

• Mass of object , m = 39 kg.
• Acceleration , a = 10 m/s².

TO FIND :-

• Amount of force applied , F.

SOLUTION :-

$\\ : \implies \displaystyle \sf \: Force = mass \times Acceleration$

$: \implies \displaystyle \sf \: Force =39 \: kg \times 10 \: ms ^{ - 2}$

$: \implies \displaystyle \sf \: Force =390 \: kg.ms ^{ - 2}$

$: \implies \underline{ \boxed{\displaystyle \sf \: Force =390 \: N}}$

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$\\ \underline{ \bigstar\textsf {Equations of motion}}$

$\bullet\displaystyle \sf \:v = u + at$

$\bullet\displaystyle \sf \: s = ut + \frac{1}{2} \times at ^{2}$

$\bullet\displaystyle \sf \: v ^{2} - u ^{2} = 2as$