Question

ncert grade 9 an object of mass 39 kg produces an accelaration of 10 m/s ² by the application of cirtum amount of force find the force ​

Answer 1

Answer:

GIVEN :-

• Mass of object , m = 39 kg.

• Acceleration , a = 10 m/s².

TO FIND :-

• Amount of force applied , F.

SOLUTION :-

$\\ : \implies \displaystyle \sf \: Force = mass \times Acceleration$

$: \implies \displaystyle \sf \: Force =39 \: kg \times 10 \: ms ^{ - 2}$

$: \implies \displaystyle \sf \: Force =390 \: kg.ms ^{ - 2}$

$: \implies \underline{ \boxed{\displaystyle \sf \: Force =390 \: N}}$

________________…

$\\ \underline{ \bigstar\textsf {Equations of motion}}$

$\bullet\displaystyle \sf \:v = u + at$

$\bullet\displaystyle \sf \: s = ut + \frac{1}{2} \times at ^{2}$

$\bullet\displaystyle \sf \: v ^{2} - u ^{2} = 2as$

Answer 2

Answer:

• The required force = 390 Newton

Given:

• The given mass of the object is 39 kg.
• The given acceleration is 10 m/s².

Need to find:

• The required force = ?

Solution:

Formula used here:

• F = M × A

Putting the values:

➜ The required force = 39 × 10

➜ The required force = 390 Newton

Therefore:

• The required force is 390 Newton.

━━━━━━━━━━━━━━━━━━━━━

Additional Information:

In Formula:

• F is used for Force.
• M is used for Mass.
• A is used for Acceleration.

━━━━━━━━━━━━━━━━━━━━━