Question

Ncert maths 9th std
Root 3+ root2divided by root3-root 2 ratioalize the denominator
*rk

Answer 1

Answer:

5 + 2√6

Step-by-step explanation:

hope it's helpful

Answer 2

Root3+root2÷root3-root2

By rationalising the denominator

= [(Root3+root2)×(root3+root2)]÷

[(Root3-root2)×(root3+root2)]

= (Root3+root2)^2 ÷ [(root3)^2-(root2)^2]

= [(Root3)^2+(root2)^2+2(root3)(root2)]÷(3-2)

In numerator we use the identity of whole square of a and b and in denominator we use identity of (a+b)(a-b)

=(3+2+2root6)÷1

=5+2root6

Hope it will help u

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