Question

NCERT physics class 12th

Q 》A man is standing on top of a building 100m. He throws two balls vertically. One at t = 0sec and after a time interval( less than 2 seconds ). The second ball is thrown at velocity of half the first. At t = 2sec. Both the balls reach to their maximum heights. At this time the vertical gap between first and second ball is 15m. Find the time interval between the throw of balls.

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Answer 1

★ Given Question ★

A man is standing on top of a building 100m. He throws two balls vertically. One at t = 0sec and after a time interval( less than 2 seconds ). The second ball is thrown at velocity of half the first. At t = 2sec. Both the balls reach to their maximum heights. At this time the vertical gap between first and second ball is 15m. Find the time interval between the throw of balls and also the speed of the first ball. ( Take g: 10m/s² )

★ Some Terms To Note ★

• Time Gap = It is the differences of the objects ( here it's balls ). projected in the time variation of a point.

• Projected = The source in which an object is launched or thrown. Here the projected body is man and the object is balls.

• Vertical Gap = The differences in height of the objects projected.

★ Answer ★

Kindly refer to the Above Attachment. ( Answer )