Question

ncert q16 maths ex 2.5 answer
both​

Answer 1

Answer:

class 9 cbse chapter 2 -polynomials

we should do direct factorisation

1) 3x²-12x

3x(x-4)

(3x) (x-4) are two possible expressions

2) 12ky²+8ky-20k

4k(3y²+2y-5)

4k (3y²-3y+5y-5)

4k [3y(y-1)+5(y-1)]

(4k) (3y+5) (y-1) are three possible expressions

Answer 2

Answer:

Let's solve the problem

Step-by-step explanation:

1. 3x²-12x

=>3x (x-4x)

=> (3x) (x-4x) is the answer.

2. 12ky²+8ky-20k

=> 4k(3y²+2y-5)

=>4k[3y²-3y+5y-5]

=>4k[3y(y-1)+5(y-1)]

=>4y(y-1)(3y+5)

So 1st answer is (3x) (x-4x)

And 2nd one is 4y (y-1) (3y+5)

I hope it will help you