Question

NCERT question after rationalising the denominator of 7 apon 3√3-2√2

Answer 1

doed it's easy
I have Gevin the answer in the image............





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Answer 2

7/(3√3-2√2)
=7(3√3+2√2) / (3√3-2√2) (3√3 +2√2)
=( 21√3 + 14√2) / (27 - 8)
= ( 21√3 + 14√2) / (27 - 8)
= ( 21√3 + 14√2) / 19
= ( 21√3) /19 + (14√2) / 19