NCERT Questions
1 Use Euclid's division algorithm to find the HCF of:
(i) 135 and 225
(ii) 196 and 38220
Answers
Answer:
1. HCF = 45
2. HCF = 196
Step-by-step explanation:
* The HCF is always the divisor ( b ) that remains when the remainder becomes 0
keys -
a = dividend b = divisor q = quotient r = remainder
Euclid division algorithm : a = bq + r
Q.1
- a = 225 b = 135
135 ) 225 ( 1
135
------------
90
-----------
q = 1
225 = 135 x 1 + 90
where r = 90 ≠ 0
- a = 135 b = 90
90 ) 135 ( 1
90
--------------
45
----------------
q = 1
135 = 90 x 1 + 45
where r = 45 ≠ 0
- a = 90 b = 45
45 ) 90 ( 2
90
------------
0
------------
q = 2
90 = 45 x 2 + 0
where r = 0 = 0
So we can stop the division now as we got the remainder = 0
∴ The HCF of 225 and 135 = 45
Q.2
- a = 196 b = 38220
195 ) 38220 ( 195
196 ↓ |
---------- |
1862 |
1764 |
---------- ↓
980
980
---------------
0
----------------
a = 38220 b = 196 q = 195
38220 = 196 x 195 + 0
where r = 0 = 0
So we can stop the division now as we got the remainder = 0
∴ The HCF of 38220 and 196 = 196
HOPE IT HELPS ..
1. Use Euclid's division algorithm to find the HCF of:
(i) 135 and 225
(i) 196 and 38220
As you can see, from the question 225 is greater than 135.
Therefore, by Euclid’s division algorithm, we have,
Now, remainder 90 ≠ 0, thus again using division lemma for 90, we get,
Again, 45 ≠ 0, repeating the above step for 45, we get,
The remainder is now zero, so our method stops here.
Since, in the last step, the divisor is 45, therefore, HCF (225,135) = HCF (135, 90) = HCF (90, 45) = 45.
In this given question, 38220 >196, therefore the by applying Euclid’s division algorithm and taking 38220 as divisor, we get,
We have already got the remainder as 0 here. Therefore, HCF(196, 38220) = 196.
Thank you!
@itzshivani