Question

Ncha is the girl in the class
a) Good
(b) better
de usually the newspaper every
a) read
(b) reads
now.
1) Rain
(b) rains
have three computer courses.​

Answer 1

Answer:

We have been given:

Potential difference across the circuit = EMF of the battery = 9V

Since all the resistances are in series combination the current flowing though each of them will be same and only the potential difference across each will vary which means if you're able to calculate current through any/all off the resistor/s there you'll get the current though each of them

Let's begin with Net resistance in the circuit first to get current.

\begin{gathered}\\\tt R_{net}\end{gathered}

R

net

= 1Ω + 2 Ω +3Ω = 6 Ω

Using Ohm's law,

V=IR

where V = potential difference across resistor with resistance R and has current I.

9 V = I (6 Ω)

\begin{gathered}\\\tt I = \dfrac{9 V}{6 \text{\O}mega } \\\tt = \dfrac{3}{2} A \\\tt = 1.5 A\end{gathered}

I=

6Ømega

9V

=

2

3

A

=1.5A

This will be current though each of the resistor which includes 3 Ω.

Answer 2

Answer:

please mark in brinliest