Ncl3 molecules is pyramidal and bcl3 molecules are planar because
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BCl3 has no lone pair of electrons while NCl3 has a lone pair of electrons.Boron has only 3 valence electrons, so when it bonds with F there will only be 3 electron pairs around the boron atom. Repulsion theory predicts that these three e- pairs should find themselves at the vertices of an equilateral triangle (bond angles of 120 degrees). Thus, BF3 is planar triangular.
Nitrogen has 5 valence electrons, three unpaired “bonding electrons” as well as one lone pair. When N bonds with H there will be a total of 4 e-pairs around the N atom. Repulsion theory predicts that these 4 e-pairs will end up at the vertices of a tetrahedron (triangular based pyramid). Hence, NH3 is trigonal pyramidal.
Nitrogen has 5 valence electrons, three unpaired “bonding electrons” as well as one lone pair. When N bonds with H there will be a total of 4 e-pairs around the N atom. Repulsion theory predicts that these 4 e-pairs will end up at the vertices of a tetrahedron (triangular based pyramid). Hence, NH3 is trigonal pyramidal.
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I have described the answer as per my knowledge. The concept of hybridization and bond pair, lone pair must be understood well to have quick answer of such type of questions. Thank you. hope it Will help.
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