Question

nd: A car at rest acclerates Uniformly to a speed of 90 km per hour in 30 s. How much distance is covered by the car.
8​

Answer 1

Answer:

Explanation:

Data:

Final velocity=90 km

time= 30 s

distance=?

Initial velocity=0 m/s

Solution

using first eqn of motion:

Vf=Vi+at

90=0+a(30)

90/30=a

3=a

Now use 3rd eqn of motion:

2as=$Vf^{2} -Vi^{2}$

2(3)s=$(90)^{2}$-0

6s=8100

s=8100/6

s=1350