Math, asked by simi11266, 5 months ago

nd help
don't give irrevelent answers
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Answers

Answered by sanji1922
3

Answer:

In triangles MNQ and PQN,

MQ = PN (Given)

QN = QN (Common side)

Angle PQN = Angle MNQ (Given)

By RHS congruence criterion,

Triangle MNQ is congruent to triangle PQN.

Hence proved.

Hope this helps :)


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Answered by Anonymous
15

In ∆ MNQ & ∆ PQN,

QN = QN (common side)

MQ = PN (given)

<Q = <N (each 90°)

by RHS congruence,

∆ MNQ is congruent to ∆ PQN


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