nd help
don't give irrevelent answers
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rajatkant82:
hi
Answers
Answered by
3
Answer:
In triangles MNQ and PQN,
MQ = PN (Given)
QN = QN (Common side)
Angle PQN = Angle MNQ (Given)
By RHS congruence criterion,
Triangle MNQ is congruent to triangle PQN.
Hence proved.
Hope this helps :)
Answered by
15
In ∆ MNQ & ∆ PQN,
QN = QN (common side)
MQ = PN (given)
<Q = <N (each 90°)
by RHS congruence,
∆ MNQ is congruent to ∆ PQN
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