nd the shortest distance between the lines whose and 7=(1-1)+ (1-2)] + (3–20) 2 7 = (s+1)+(23-1)-(2+1
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Answer:
Solution
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Correct option is
D
35
We have,
−1
x−3
=
2
y−4
=
1
z+2
r
1
=3
i
+4
j
−2
k
+λ(−
i
+2
j
+
k
)
1
x−1
=
3
y+7
=
2
z+2
r
2
=
i
−7
j
−2
k
+λ(
i
+3
j
+2
k
)
d=
∣(−
i
+2
j
+
k
)×(
i
+3
j
+2
k
)∣
∣(2
i
+11
j
).(−
i
+2
j
+
k
)×(
i
+3
j
+2
k
)∣
=
∣(
i
+3
j
−5
k
)∣
∣(2
i
+11
j
).(
i
+3
j
−5
k
)∣
=
35
∣35∣
=
35
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