Question

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30. Two masses of 10 hands are suspended
from a rigid support as shown in figure, The
system is pulled down with a fores of 1547
attached to the lower mase. The string
attached to the support breaks and the system
secelerates downwards
te
In case the force continues to act what will be
the tension acting between the two masses?
1) 300 N 2) 200 N 3) 100 N
Two​

Answer 1

Answer:

This implies that

x2+2ax=4x−4a−13

or

x2+2ax−4x+4a+13=0

or

x2+(2a−4)x+(4a+13)=0

Since the equation has just one solution instead of the usual two distinct solutions, then the two solutions must be same i.e. discriminant = 0.

Hence we get that

(2a−4)2=4⋅1⋅(4a+13)

or

4a2−16a+16=16a+52

or

4a2−32a−36=0

or

a2−8a−9=0

or

(a−9)(a+1)=0

So the values of a are −1 and 9.