Question

ne end of a string 1m long is fixed and a body of mass 500g is tied to the other end. If the

breaking tension is 98 N, find the maximum angular velocity of the body that the string can

withstand when rotated in a horizontal circle. [ώmax. = 14 rad/s] [OCTOBER 1994]​

Answer 1

Answer:

14 rad/s

PLZ:

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Explanation:

mass=0.5KG

T=98N

T=mώ²r

98=0.5(ώ)²1

196=(ώ)²

ώ=14

hope this helps

Answer 2

Answer:

The maximum value of angular acceleration is 14 rad/s.

Explanation:

Given is a string of length 1m on which a body of mass 0.5kg is tied.

Its breaking tension given is of 98N.

When it is rotated in a horizontal circle the centrifugal force acts on it which is given by,

$F_{centrifugal}=mrw^{2}$

where r is the radius of the horizontal circle and $w$ is the angular velocity of the body.

For maximum Angular Velocity,

$F_{centrifugal}\leq breaking\ Tension\\mrw^{2} \leq 98\\0.5*1*w^{2}\leq 98\\w^{2}\leq 196\\w\leq 14$

Hence, The maximum value of $w$ is 14 rad/s.