Question

Ne* ions in a neon advertising tube
How many electrons have to be removed to ionize 1.0 X 106 moles of Ne atoms
6.022 x 1022
B) 1
3
C) 1.0 x 10-6 x 6.02 x 1023
A)
6.02 x 1023
1.0x106
1.0x10x6.02x1023
20.2
1.0x100x6.02 x 1023
D)
9.65 x 10-
B)
.​

Answer 1

Answer:

Explanation:

Well, look at your stoichiometric equation…

Ne(g)+Δ→Ne+(g)+e−  

If we ionize a MOLE of neon atoms, then we get a mole of neon cations, AND a mole of electrons; conservation of mass and charge ASSURES this outcome. If we ionize a DOZEN neon atoms, then we get a DOZEN neon cations, AND a DOZEN electrons. And so should we ionize  1.0×10−6∙mol  neon atoms, then we get  1.0×10−6∙mol  neon CATIONS, AND a  1.0×10−6∙mol  quantity of electrons… And we go farther than this … if we are quoted the ionization enthalpy of neon gas in  kJ∙mol−1 ,

so answer 6.02 x 10 to the 17