Physics, asked by aravindsriram569, 10 months ago

ne is dropped from the top of a cliff of height hin second later a sec
the same cliff with a vertically downward velocity u. Show that the two stones will reach the bottom
cliff together, if gh(u-gn)"
gw (211- gn)
eys:
rah
ticle moving in a straight line is observed to be at a distance 'a' from a marked point initially, at a
ce 'b' after an interval of n seconds, to be at a distance 'c' after 2n seconds and at a distance 'd'
In seconds. Prove that if the acceleration is uniform, d-a=3(c-b) and that the acceleration is equal
a-26
n?​

Answers

Answered by vishalchowdary
1

Answer:

Explanation:

A stone is dropped from the top of a cliff of height h. ''n'' seconds later, a second stone is projected downwards from the same cliff with a vertically downward velocity u. Show that the two stones will reach the bottom of the cliff together, if 8h(u-gn)^(2) = gn^(2)(2u - gn)^(2) what can you say about the limiting value of ''n'' ?

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