Question

near point of hypermetropic eyes using power +3D​

Answer 1

Answer:

Ok sure mate

Explanation:

The normal near point of an eye is 25 cm. ... The virtual image must be for med at 100 cm for a hypermetropic eye with a near point of 1 m (100 cm) to see an object placed at 25 cm. According to the formula - 1/focal length (f)= 1/ object distance (u) + 1/ image distance (v) or 1/f = 1/u -1/v.