Question

Near the earth's surface time period of a satellite is 1.4 hrs.Find its time period if it is at the distance 4R from the centre of earth

Answer 1

according to kepler second law

Answer 2

Dear Student,

◆ Answer -

T' = 11.2 hours

● Explanation -

Time period of satellite is related to its distance from centre of earth as -

T^2 ∝ r^3

Hence,

(T'/T)^2 = (R'/R)^3

(T'/1.4)^2 = (4R/R)^3

(T'/1.4)^2 = 4^3

T'^2/1.96 = 64

T'^2 = 64 × 1.96

T'^2 = 125.44

T' = 11.2 hours

Hence, new time period is 11.2 hours.

Thanks dear. Hope this helps you...