Question

near the earth surface the time period of satellite in meters​

Answer 1

Answer:

For a satellite revolving very near to the earth's surface the time period of revolution is given by 1h 24min.

Reason

The period of revolution of a satellite depends only upon its height above the earth's surface.

A Both Assertion and Reason are correct and Reason is the correct explanation for Assertion

B Both Assertion and Reason are correct but Reason is not the correct explanation for Assertion

C Assertion is correct but Reason is incorrect

D Assertion is incorrect and Reason is correct

ANSWER

We know orbital velocity of a satellite around a planet of massM

having radius of orbit

(r>

R)

V

0

=

r

GM

Time period

=

V

2πr

=

GM

2πr

r

=

2π

G M

R 3

here G and M are constant

$$|Rightarrow Time period depends only on radius (height above earth)

∴ Time perois for satellite near earth surface

= 2π

g

R

=

sqrtπ

2

2π

×

6400×1000

[∵

g≈

π 2

= 2× 800×

1

0seconds=

60

2×800

×

1

0min

= 84min= 1hr+ 24min

Explanation:

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Answer 2

Answer:

I have two answer

(a) radius of the earth is 6400km

(b) the period of revolution of a satellite depend only upon its height above the earth,surface