Question

Need a Well Explained Answer!

Answer 1

Given:

• A bird flying at a height of 40 ft above the ground.
• An 8 ft ledge.
• The top of the ledge is at a 22° angle of depression from the bird.

To find: How far the bird must fly for it to land on the ledge.

Answer:

(Diagram for reference attached below.)

Let's first try and understand the difference between the height at which the bird is flying and the length of the ledge.

The 8 ft constitutes a part of the 40 ft. Hence the remaining height will be:

40 - 8 = 32 ft.

Now, consider Δ ABC.

$\tt sin\ {22}^{\circ}\ =\ \dfrac{32}{x}$

(sin 22° = 0.374 [approx.])

$\tt 0.374\ =\ \dfrac{32}{x}\\\\\\x\ =\ \dfrac{32}{0.374}\\\\\\x\ =\ 85.5614\ ft\ [approx.]$

Therefore, the bird must fly a distance of about 85.56 ft to reach the ledge.

Answer 2

Step-by-step explanation:

bird flying at a height of 40 ft above the ground.

An 8 ft ledge.

The top of the ledge is at a 22° angle of depression from the bird.

To find: How far the bird must fly for it to land on the ledge.

Answer:

(Diagram for reference attached below.)

Let's first try and understand the difference between the height at which the bird is flying and the length of the ledge.

The 8 ft constitutes a part of the 40 ft. Hence the remaining height will be:

40 - 8 = 32 ft.

Now, consider Δ ABC.

\tt sin\ {22}^{\circ}\ =\ \dfrac{32}{x}sin 22

∘

=

x

32

(sin 22° = 0.374 [approx.])

\begin{gathered}\tt 0.374\ =\ \dfrac{32}{x}\\\\\\x\ =\ \dfrac{32}{0.374}\\\\\\x\ =\ 85.5614\ ft\ [approx.]\end{gathered}