need all answers of questions with solution plz
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not getting 1 & 2 but got the 3 one
3) as we know that if D & E would be the mid points of AB & AC then DE would be parallel to BC (by mid pt thm)
in which AD = BD = 50% of total,
but here we have
AD = 5.7cm
BD = 9.5cm i.e. AB = AD+BD = 5.7+9.5 = 15.2
so AD = 37.5% of AB and
AE = 3.3cm
CE = 5.5cm i.e. AC = AE + BE = 3.3 + 5.5 = 8.8
so AE = 37.5% of AC
there fore DE parallel to BC
3) as we know that if D & E would be the mid points of AB & AC then DE would be parallel to BC (by mid pt thm)
in which AD = BD = 50% of total,
but here we have
AD = 5.7cm
BD = 9.5cm i.e. AB = AD+BD = 5.7+9.5 = 15.2
so AD = 37.5% of AB and
AE = 3.3cm
CE = 5.5cm i.e. AC = AE + BE = 3.3 + 5.5 = 8.8
so AE = 37.5% of AC
there fore DE parallel to BC
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iii , here u go for it .
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