Question

NEED AN ANSWER!!! RIGHT NOW!!! ​

Answer 1

Explanation:

Prove that area of a trapezium is equal to half the product of the sum of parallel sides and distance between the parallel sides.

Medium

ANSWER

Consider the trapezium ABCD with with AB∣∣toCD

∴AP=BQ=h(say) [distance between parallel lines one equal]

ar(ABCD)=ar(△ADC)+ar(△ABC)

.....(2)

ar(△ADC)=

2

1

×base×height=

2

1

×(DC)×h

......(1)

ar(△ABC)=

2

1

×base×height=

2

1

×(AB)×h

.....(3)

From (1),(2) and (3)

ar(ABCD)=

2

1

×h(CP)+

2

1

h(AB)

ar(△ABCD)=

2

1

h[AB+CD]

∴

areaoftrapezium=halfofproductheightofheightandsumofparallelsides.

solution

Answer 2

Answer:

Ordered list

Explanation:

Start Attribute: specifies the start value of an ordered list

Type Attribute: specifies the type of the list item marker