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Here a=3.
d =a2-a1=(-10)-3=-13.
amd this is in a A.P.
So,nTH term of the Sequence=a+(n-1)d
=3+(n-1)(-13)
=3-13n+13
=16-13n. →(1)
15TH term.
(1)→16-13(15)=16-195=(-179).
-114.
16-13n=(-114)
→-13n=(-114)-16
→-13n=-130
→13n=130
→n=130/13=10TH term.
Hope it Helps...
Regards,
Leukonov.
d =a2-a1=(-10)-3=-13.
amd this is in a A.P.
So,nTH term of the Sequence=a+(n-1)d
=3+(n-1)(-13)
=3-13n+13
=16-13n. →(1)
15TH term.
(1)→16-13(15)=16-195=(-179).
-114.
16-13n=(-114)
→-13n=(-114)-16
→-13n=-130
→13n=130
→n=130/13=10TH term.
Hope it Helps...
Regards,
Leukonov.
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d =a2-a1=(-10)-3=-13 . could u make this more clear?
The common difference of an AP is the difference of the Second and first term.
i.e. common difference,d=second term(a2) - first term (a1)
or a3-a2 or a4-a3 ....
got it!!
in general... d= (n+1)TH term - nTH term. or d=nTH term - (n-1)TH term.
okay. do you want to know anything else?... Feel free to ask okay. if i can i will answer it .(^_^)
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