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Let us say that the side lengths are aa and the bottom length is 6−2a6−2a. By using pythagorean theorem we can conclude that the height hh is equal to 6a−9−−−−−√6a−9. Then, the area of the triangle can be given as f(a)=(3−a)(6a−9−−−−−√)f(a)=(3−a)(6a−9). So f′(a)=−6a−9−−−−−√+36a−9−−−−−√f′(a)=−6a−9+36a−9. Finally, f′(a)=12−6a6a−9−−−−
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