Question

need answer


class 10 maths

​

Answer 1

For a taxi or auto, generally fare charges are fixed fir some km then according to the distance covered.
So let x be the fixed charge for first 10 km and y be the additional charges per km.
Then, For 50 km, x + 40y = 330
For 90 km , x + 80y = 610
On solving both we get,
y=7 and x= 50