Question

need answer fast please

Answer 1

$\bf{Given : \frac{1 + Sin\alpha}{1 - Sin\alpha} = \frac{m^2}{n^2}}$

$\bf{Applying\;Componendo\;and\;Dividendo\;Theoram\;on\;Both\;Sides}$

$\bf{\implies \frac{(1 + Sin\alpha) + (1 - Sin\alpha)}{(1 + Sin\alpha) - (1 - Sin\alpha)} = \frac{m^2 + n^2}{m^2 - n^2}}$

$\bf{\implies \frac{1}{Sin\alpha} = \frac{m^2 + n^2}{m^2 - n^2}}$

$\bf{\implies Sin\alpha = \frac{m^2 - n^2}{m^2 + n^2}}$

Option (b) is the Answer