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for a rxn in equilibrium 2NOCl<=>2NO + Cl2.If partial pressure of Cl2 is P/4 where P is the initial pressure of NOCl. Find total pressure at equilibrium
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Explanation:
K
P
=K
C
.(RT)
Δng
⇒K
C
=3.75×10
−4
⇒T=1069K
Δng= moles of product- moles of reactant
Δng=3−2=1
⇒K
P
=3.75×10
−4
×(8.314×1069)
1
⇒K
P
=3.33
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