need answer for this
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Answer:
Given ; length of walls = 7 m
breadth of walls = 5 m
height of walls = 3 m
area of four walls = L.S.A of walls
L.S.A. of walls = 2(l+b)h
= 2 (7 + 5 )3
= 12 × 6
= 72 m^2
total cost of white washing = cost/m^2 × area of four walls
= 10 × 72
= 720 RS
Answered by
0
Answer:
area of four walls
=2(l+b)h
=2(7+5)3
=2(12)3
=72m^2
cost of white washing
=72×10
=₹720
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