Math, asked by tanveerjot, 24 days ago

need answer to both parts please​

Attachments:

Answers

Answered by tennetiraj86
4

Step-by-step explanation:

Solution :-

General method :-

Given numbers are 1.3 bar and 1.4 bar

1.3 bar = 1.333...

1.4 bar = 1.444...

Two rational numbers between them

= 1.3222... and 1.43333...

Mean Method :-

Let X = 1.333...------------(1)

since the periodicity is 1 then multiply (1) with 10

=> 10×X = 1.333...×10

=>10X = 13.333...--------(2)

(2)-(1)

10X = 13.333...

X = 1.333...

(-)

____________

9X = 12.000...

____________

=> 9X = 12

=> X = 12/9

=> X = 4/3

and

Let X = 1.444...------------(1)

since the periodicity is 1 then multiply (1) with 10

=> 10×X = 1.444...×10

=>10X = 14.444...--------(2)

(2)-(1)

10X = 14.444...

X = 1.444...

(-)

____________

9X = 13.000...

____________

=> 9X = 13

=> X = 13/9

Now we have 12/9 and 13/9

The rational number between them by mean method (a+b)/2

=> [(12/9)+(13/9)]/2

=> (25/9)/2

=> 25/18

and Second rational number

=>[(12/9)+(25/18)]/2

=> [(24+25)/18]/2

=> (49/18)/2

=> 49/36

The two rational numbers between them are 25/18 and 49/36

ii)General method :-

Given numbers are 2.23 bar and 2.24 bar

2.23 bar = 2.232323...

2.24 bar = 2.242424...

Two rational numbers between them

= 2.232525... and 2.239899...

Mean Method :-

Let X = 2.232323...------------(1)

since the periodicity is 2 then multiply (1) with 100

=> 100×X = 2.232323...×100

=>100X = 223.232323...--------(2)

(2)-(1)

100X = 223.232323...

X = 2.232323...

(-)

__________________

99X = 221.000000...

__________________

=> 99X = 221

=> X = 221/99

and

Let X = 2.242424...------------(1)

since the periodicity is 2 then multiply (1) with 100

=> 100×X = 2.242424...×10

=>100X = 224.242424...--------(2)

(2)-(1)

100X = 224.242424...

X = 2.242424...

(-)

_________________

99X = 222.000000

_________________

=> 92X = 222

=> X = 222/99

Now we have 221/99 and 222/99

The rational number between them by mean method (a+b)/2

=> [(221/99)+(222/99)]/2

=> (443/99)/2

=> 443/198

and Second rational number

=>[(221/99)+(443/198)]/2

=> [(442+443)/198]/2

=> (885/198)/2

=> 885/396

The two rational numbers between them are 443/198 and 885/396

Used formulae:-

.Mean Method :-

The rational number between the two numbers a and b is (a+b)/2

Similar questions