Question

NEED ASAP: how many ounces of pure nickel must be added to 150 ounces of alloy 70% pure to make an alloy 85%

Answer 1

Answer:

Step-by-step explanation:

let x = the amount of nickel to be added to the mixture.

your formula will be:

.7*150 + x = .85(150 + x)

simplify this to get:

.7*150 + x = .85*150 + .85*x

subtract .85*x from both sides of this equation to get:

.7*150 + .15*x = .85*150

subtract .7*150 from both sides of this equation to get:

.15*x = .85*150 - .7*150

simplify to get:

.15*x = 22.5

divide both sides of this equation by .15 to get:

x = 22.5 / .15 = 150

this means you need to add 150 ounces of nickel to the mixture to get an allow that's 85% nickel.

150 + 150 = 300 ounces in the new mixture.

the amount of nickel in the new mixture is equal to:

.7 * 150 + 150 = 105 + 150 = 255 ounces of nickel in the next mixture.

the percent nickel in the new mixture is 255 / 300 = .85 = 85%.