Question

NEED ASAP PLEASE
how do you solve
1-v-v=v-5-2v
-5a-27=4(2-3a)
32-2x=-5(x+2)-4x
-(2+6b)+2b=-8-5b
4a+16=8a-4(-2a-7)
-8(3n-3)=-(6-6n)
7+4r+3r=-2(r-2)+2(r-2)

Answer 1

Answer:1-v-v=v-5-2v

1+5=+2v+v-2v

6=v

v=6

-5a-27=4(2-3a)

-5a-27=8-12a

12a-5a=27+8

7a=35

a=5

32-2x=-5(x+2)-4x

32-2x=-5x-10-4x

7x=-42

x=-6

-(2+6b)+2b=-8-5b

-2-6b+2b=-8-5b

-6b+2b+5b=-8+2

b=-6

4a+16=8a-4(-2a-7)

4a+16=8a+8a+28

a=12/12

1

-8(3n-3)=-(6-6n)

-24n+24=-6+6n

30=30n

n=1

7+4r+3r=-2(r-2)+2(r-2)

7+4r+3r=-2r+4+2r-4

7r=-7

r=-1

Answer 2

Answer:

Step-by-step explanation:

Answer:1-v-v=v-5-2v

1+5=+2v+v-2v

6=v

v=6

-5a-27=4(2-3a)

-5a-27=8-12a

12a-5a=27+8

7a=35

a=5

32-2x=-5(x+2)-4x

32-2x=-5x-10-4x

7x=-42

x=-6

-(2+6b)+2b=-8-5b

-2-6b+2b=-8-5b

-6b+2b+5b=-8+2

b=-6

4a+16=8a-4(-2a-7)

4a+16=8a+8a+28

a=12/12

1

-8(3n-3)=-(6-6n)

-24n+24=-6+6n

30=30n

n=1

7+4r+3r=-2(r-2)+2(r-2)

7+4r+3r=-2r+4+2r-4

7r=-7

r=-1